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x^2-320x+11200=0
a = 1; b = -320; c = +11200;
Δ = b2-4ac
Δ = -3202-4·1·11200
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-240}{2*1}=\frac{80}{2} =40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+240}{2*1}=\frac{560}{2} =280 $
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